The sum of two numbers is 8/3 and the difference is 1/3. find them
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Step-by-step explanation:
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Answered by
3
Answer:
Therefore, two numbers are 3/2 and 7/6
Step-by-step explanation:
Let the two numbers be x and y ( Assuming that x>y)
- Since, Sum of the two numbers is 8/3
So,
x + y = 8/3
=>3(x + y) = 8
=> 3x + 3 y = 8 --------------------(i)
- And difference of the two numbers is 1/3
So,
x - y = 1/3
=> 3x - 3y = 1 -------------------------(ii)
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Now, adding equation (i) and (ii) we get,
3x + 3y + 3x - 3y = 8 + 1
=>6x = 9
=>x = 9/6
=>x = 3/2
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Now putting the value of x = 2/3 in equation (i) we get,
3*(3/2) + 3y = 8
=> 9/2 + 3y = 8
=> 3y = 8 - 9/2
=> 3y = 7/2
=> y = 7/6
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Therefore, two numbers are 3/2 and 7/6
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