the sum of two numbers is 8 and sum of their reciprocals is 8/5 find the numbers
jeshu2103:
kkkkkkkkkkkkkk'
wats ur problem
crude
sugar honey ice tea
think i solved it
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Let number be x and (8-x)
1/x + 1/(8-x)=8/5
(8-x)/(8x-x^2) + x/(8x-x^2) =8/5
8/(8x-x^2) =8/5
5=8x - x^2
Then do quadratic for x^2 - 8x + 5
1/x + 1/(8-x)=8/5
(8-x)/(8x-x^2) + x/(8x-x^2) =8/5
8/(8x-x^2) =8/5
5=8x - x^2
Then do quadratic for x^2 - 8x + 5
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