Question

the sum of two numbers is 8 and the difference between the squares is 32​

Answer 1

Answer:

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Step-by-step explanation:

Let the numbers be x and y

according to the question

x+y=8        (1)

therefore y=8-x

$x^{2} -y^{2}$  = 32

(x+y)(x-y) = 32

8(x-(8-x)) = 32

8(2x-8) = 32

16x-64=32

x=96/16

therefore x=6

and y =8-x

=> y=2

hope it helps you