the sum of two numbers is 8 and the difference is 32 find the numbers
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given sum of two numbers =8
let the numbers be x and y
x+y=8( eq 1)
also given there difference is 32
x-y=32
x=32+y ( substitute in eq2)
x+y=8
(32+y)+y=8.
32+2y=8
2y=8-32
2y= -24
y= -12
now to get the value of x substitute the value of y in equation 1.
x+y=8
x-12=8
x=20
therefore the value of x and y are -12 and 20
hope it helps!!!
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