the sum of two numbers is 8 and the difference is 33 find the numbers
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Answer:
x=41/2
y=-25/2
Step-by-step explanation:
let be first number is x
and second number is y
the sum of number is 8 =x+y--------------{ 1 }
the difference is 33=x-y------------{2}
=x+y=8
=x-y=33
equation (2)
x-y=33
x=33+y--------(3)
equation (1) and (3)
=x+y=8
=(33+y)+y=8
=33+2y=8
=2y=8-33
=y=-25/2------(4)
equation (2)and(4)
=x-y=33
=x-(-25/2)=33
=x=33-25/2
=x=66/2-25/2
x=66-25/2
x=41/2
x=41/2
y=-25/2
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