Question

The sum of two numbers is 8 and the difference
of their squares is 32. Find the numbers.​

Answer 1

Step-by-step explanation:

x+y=8

(x+y)(x-y)=32

x-y=4

2x=12

x=6

y=8-6=2

Answer 2

Solution

Given that :-

• sum of two numbers is 8
• difference
• of their squares is 32

Find :-

• These two Number.

Explanation

Let,

• First Number be = x
• Second Number be = y

A/C to question,

(sum of two numbers is 8)

==> x + y = 8 -----------(1)

Again,

(difference of their squares is 32)

==> x² - y² = 32 -----------(2)

[ ( a² - b²) = (a-b)(a+b)]

==> (x+y)(x-y) = 32

Keep Value by equ(1)

==> (x - y ) * 8 = 32

==> x - y = 32/8

==> x - y = 4 ----------(3)

add equ(1) & equ(3)

==> 2x = 8 + 4

==> 2x = 12

==>x = 12/2

==> x = 6

Keep Value of x in equ(3)

==> 6 - y = 4

==> y = 6 - 4

==> y = 2

Hence

• Value of x = 6
• Value of y = 2

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