Question

The sum of two numbers is 8 and the difference of their squares is 32. Find the numbers.​

Answer 1

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Answer 2

Solution

Given:-

The sum of the numbers is 8

difference of their squares is 32

Find:-

These two number .

Explanation

Let,

first number = x

Second number = y

A/C to question

(The sum of the numbers is 8)

==> x + y = 8 ------------equ(1)

Again,

(difference of their squares is 32 )

==> x² - y² = 32

We know,

★ (x²-y²) = (x+y)(x-y)

So,

==> (x+y)(x-y) = 32

keep value by equ(1)

==> x - y = 32/8

==> x - y = 4 ----------------equ(2)

Now, Add equ(1) & equ(2).

==> 2x = 12

==> x = 12/2

==> x = 6

keep value of x in equ(2),

==> 6 - y = 4

==> y = 6 - 4

==> y = 2

Hence

Value of first number = x = 6

Value of second number = y = 2

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