Math, asked by siddeshwar7338, 1 year ago

the sum of two numbers is 8 and the sum of their squares is 34 taking one number as x, form an equation in x and solve it to find the numbers.

Answers

Answered by alivia07
13

Let one no. be x

And the other be y

x + y = 8

x^2 + y^2 = 34

x = 5

y = 3

5 + 3 = 8

5^2 + 3^2 = 34

25 + 9 = 34

Answered by umarmir15
0

Answer:

The numbers are 3 and 5 or 5 and

Step-by-step explanation:

We have given in the question as

Let one number x

The sum of two numbers is 8

The, sum of their squares is 34

first number is x

the other number will be equal to

8-x ( 8 is the sum of two numbers)

Their sum of square is 34

hence we can write it as

x^2+(8-x)^2=34

x^2+64–16x+x^2=34

2x^2–16x+30

x^2–8x+15

(X-3)(x-5)=0

x= 3 or 5

Therefore he numbers are

3 and 5

Or 5 and 3

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