Question

the sum of two numbers is 8 and their squares are34 .taking one number as x form an equation in x and find the numbers .the numbers arw​

Answer 1

Step-by-step explanation:

this is correct answer according to my knowledge

Answer 2

Answer:

x=5,y=3

Step-by-step explanation:

x+y=8

x=8-y ( equation 1)

x square +ysquare=34(equation 2)

substitute equ 1 in 2

8-y whole square+y^2=34

8^2+y^2-2(8)(y)+y^2=34

64+2y^2-16y=34

2(y^2-8y+32)=34

y^2-8y+32=17

we get y=3

substituting y value in 1

we get x=5

so the numbers are 5,3