the sum of two numbers is 8 determine the numbers if the sum of their reciprocals is 8÷15
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Answer:
x+y=8
1/x+1/y=8/15
x=8-y
=1/8-y+1/y
=y+8-y/8y-y²
8/8y-y²=8/15
=8y-y²=15
8y-y²-15=0
y²-8y+15=0
y²-3y-5y+15=0
y(y-3)-5(y-3)=0
y=3,5
x=5,3
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