Question

The sum of two numbers is 8. If their difference is one fourth of their

sum, find the numbers.​

Answer 1

Answer:

The no.s are 5 and 3 ......Hope my answer helps please mark it as brainiest............

Step-by-step explanation:

let the no:s be x and y

given ,

x + y = 8

x + y = 4 [ x - y ]

x + y = 4x - 4y

8 = 4 [ x - y ]

2 =  x - y

x - y = 2

x  + y = 8

--------------------------------------------------------------

2x = 10

x = 5

x + y = 8

y = 8 - 5 = 3

--------------------------------------------------------------

the no.s are 5 and 3

Answer 2

Answer:

the numbers are 5 and 3

Step-by-step explanation:

let the numbers be x and y

so x+y=8

since the difference is one fourth of their sum

x-y=8/4=2

so x-y=2

solve both equations

x+y=8

x-y=2

on solving we get

2x=10

x=5

therefore substitute the value of x in any one of the equation we get

x+y=8

5+y=8

y=8-5

y=3

therefore x=5 and y=3

hope it helped u

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