The sum of two numbers is 8. If their sum is four times their difference,find the numbers.
Answers
Given : The sum of two numbers is 8. If their sum is four times their difference.
Solution:
Let the two numbers be x and y.
ATQ :
Condition : 1
x + y = 8 ………….(1)
Condition : 2
x + y = 4(x - y)
x + y = 4x - 4y
x - 4x = - 4y - y
-3x = - 5y
3x = 5y
3x - 5y = 0 ………..(2)
From eq 1 :
x = 8 - y ……….(3)
On Substituting the value of x in equation (2) we obtain :
3x - 5y = 0
3(8 - y) - 5y = 0
24 - 3y - 5y = 0
24 - 8y = 0
-8y = - 24
8y = 24
y = 24/8
y = 3
On putting y = 3 in eq (3) we obtain :
x = 8 - y
x = 8 - 3
x = 5
Hence, the two numbers are 5 and 3.
Hope this answer will help you…
Some more questions from this chapter :
The difference of two number is 66. If one number is four times the other, find the numbers.
https://brainly.in/question/2810787
The sum of a two digit number and number obtained on reversing the digits is99. If the number obtained on reversing the digit is 9 more than the original number,find the number. https://brainly.in/question/2818034
Step-by-step explanation:
x= 5
y = 3
hope it helps. ....
