Question

The sum of two numbers is 8. If their sum is four times their
difference, find the numbers by substitution method​

Answer 1

Step-by-step explanation:

Let one no. be x and other no. be y.

ATQ

x+y=8

x+y= 4(x-y)

x+y=4x-4y

y+4y=4x-x

5y=3x

y=3x/5

Now substituting y=3x/5 in x+y=8

x+3x/5=8

5x/5 + 3x/5= 8

8/5x=8

x= 8× 5/8

x= 5

now putting x=5 in x+y=8

5+y=8

y=8-5=3

Ans: Hence, the nos. are 5 and 3