the sum of two numbers is 8. if there sum is four times their difference . find the numbers
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Answer:
let the numbers be x, and y
x+y = 8 ......(i)
8(4)= x-y
32=x-y
x-y = 32 ......(ii)
by using simultaneous method we can solve this
adding 1st and 2nd. we get
x+y = 8
+x-y = 32
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2x= 40
x= 40/2
x= 20
put x= 20 in eqń 2nd we get
20-y= 32
y = 32-20
y = 12
Step-by-step explanation:
ans. (x,y ) (20,12)
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