The sum of two numbers is 8 while thair product is 15. Find the sum of their reciprocals. help me
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Answer:
the sum of reciprocals is 8/15
Step-by-step explanation:
let one of the no. be =x
and another be =8-x
now, their product=x(8-x) =15
8x-x^2=15
x^2+15-8x=0
x^2-8x+15=0
x^2-5x-3x+15=0
x(x-5)-3(x-5)=0
(x-3)(x-5)=0
so, the no. are zeros of the equation that are
x-5=0
x=5
and, x-3=0
x=3
now, sum of their reciprocals =1/3+1/5=5+3/15=8/15
so the sum of their reciprocals is 8/15
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