Question

The sum of two numbers is 80 amd the greater number exceed twice the smaller by 11 find the numbers

Answer 1

$<b><big>Hello Friend !!!$


$<b>Here is your answer$


$<b>Given :$


$<b>↪ Sum of two numbers = 80$


$<b>Let the smaller number be x.$


$<b>↪ Larger Number = 2x + 11$


$<b>2x + 11 + x = 80$


$<b>3x + 11 = 80$


$<b>3x = 80 - 11$


$<b>3x = 69$


$<b>x = 23$


$<b>∴ Smaller Number = 23$


$<b>∴ Larger number = 2 ( 23 ) + 11 = 57$


$<b><big>Hope It Helps$

Answer 2

$\huge\underline\mathcal\purple{Answer}$

Let the number be x

Then greater number = 2x + 11

Sum of two numbers = 80

x + 2 + 11 = 80

3x = 80 - 11

3x = 69

x = 23

Hence, smaller number = 23

Greater number = 2 × 23 + 11 = 57