Question

The sum of two numbers is 80 and the greater number exceeds twice the smaller
by 11. Find the numbers. please explain step by step​

Answer 1

Answer:

Let us assume, x and y are the two numbers and x > y

Given:

x + y = 80 -----------1

Also given:

x = 2y + 11 --------------2

Substitute the value of x from equation 1 in equation 2

2y + 11 + y = 80

3y + 11 = 80

3y = 69

y = 23

Therefore, x = 2y + 11 = (2 * 23) + 11 = 57

The two numbers are 57 and 23

Answer 2

Answer:

.

This is your answer.

please mark as brainliest please