Question

The sum of two numbers is 80 and the greater number exceeds twice the smaller number by 11.Find the number

Answer 1

Step-by-step explanation:

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Answer 2

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Let the number be x

Then greater number = 2x + 11

Sum of two numbers = 80

x + 2 + 11 = 80

3x = 80 - 11

3x = 69

x = 23

Hence, smaller number = 23

Greater number = 2 × 23 + 11 = 57