the sum of two numbers is 80 and the greater number exceeds twice of the smaller by 11. Find the numbers
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Answered by
6
X and 2x+11 gives 80
then 3x+1 gives 80
3x=69 .hence 23 and 57
then 3x+1 gives 80
3x=69 .hence 23 and 57
avijitnath5pa9ng9:
in my answers it is written 57 and 23 one answer of your have match but the second answer is not matching
sorry
no probs
Answered by
7
Smallest number-x
Greatest number -2x+11
Sum-80
Therefore
x+2x+11=80(sum of two numbers is 80)
3x+11=80
3x=80-11
3x=69
X=23
Greatest number=2×23+11=57
Smallest-23
Sum=80
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