Question

the sum of two numbers is 80 and the greatest number exceeds twice the smaller by 11 find the number

Answer 1

let the smaller number is x

greater number is 2x + 11

According to the given question

sum is 80

x + 2x+11 = 80

3x + 11 = 80

3x = 80 - 11

3x = 69

X = 69/3

X = 23.

Hence , smaller number X = 23

greater number 2x+11= 2(23) + 11 = 46 + 11 = 57

$\bold{Answer: Numbers \: are \: 23 \: and \: 57}$