Question

the sum of two numbers is 80 if one is four times the others find the numbers​

Answer 1

$\huge\sf\red{Solution}$

ANSWER

$\sf\pink{One\: number=> x=> 16}$

$\sf\pink{Other \:number=> 4x=>4×16 => 64 }$

EXPLANATION

$\sf\green{Let \:one\: number\: be\: x }$

$\sf\green{And \:other\: number \:be \:4x }$

$\sf\red{Sum \:of\: numbers= 80 }$

According.to.ques

$\huge\sf\purple{x+4x=>80}$

$\huge\sf\purple{5x=>80}$

$\huge\sf\purple{x=>{\frac{80}{5}}}$

$\huge\sf\orange{x=> 16}$

So,

• $\sf\blue{One\: number=> x=> 16}$
• $\sf\blue{Other\: number=> 4x=>4×16 =>}$$\sf\blue{ 64 }$

LET'S CHECK

$\huge\sf\pink{16+4×16=> 80}$

$\huge\sf\pink{16+64=> 80}$

Yup!! we did the sum