Question

the sum of two numbers is 80. if the larger number exceeds four times the smaller one by 5 then the smaller number is

Answer 1

$\textbf {Hey there, here is the solution.}$

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STEP 1: Define x:

Let the larger number be x.

The smaller being 80 - x.

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STEP 2: Form the equation:

The larger number exceeds 4 times the smaller one by 5:

x = 4(80 - x) + 5

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STEP 3: Solve x:

x = 4(80 - x) + 5

x = 320 - 4x + 5

5x = 325

x = 65

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STEP 4: Find the numbers:

larger number = x = 65

smaller number = 80 - x = 80 - 65 = 15

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Answer: The smaller number is 15

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⭐$\textbf {Cheers}$⭐

Answer 2

Given:

• The sum of two numbers is 82.
• The larger number exceeds four times the smaller one by 5.

To Find:

• Find the smaller number.

Solution:

Let, the larger number be x

And, the smaller number be 80 - x.

★According to the question,

→x = 4 (80 - x) + 5

→x = 320 - 4x + 5

→5x = 325

→x = 325/5

→x = 65

The numbers are,

• Larger number = x = 65
• Smaller number = 80 - x = 80 - 65 = 15

★Verification:

→65 + 15 = 80

→80 = 80

LHS = RHS