the sum of two numbers is 80.of the larger number exceeds four times the smaller one by 5,then the smaller number is:
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Answered by
7
- The larger number x = 65
- The smaller number y = 15
- The sum of two numbers is 80.
- The larger number exceeds four times the smaller one by 5.
- The smaller number is = ?
Let the larger number be x
And the smaller number be y.
The sum of two numbers is 80.
- ..... (i)
If the larger number exceeds four times the smaller one by 5.
- ..... (ii)
- The larger number (x) = 65
- The smaller number (y) = 15
Answered by
23
Given :
Sum of two number is 80
Larger number exceeds four times the smaller one by 5
To Find :
Smaller Number
Solution :
Let larger number = x
and smaller number = y
Now
According to question :
Sum of two number is 80
So x + y = 80 ... (1)
and
Larger number exceeds four times the smaller one by 5
x = 4y + 5 ... (2)
Solving equation 1 and 2
x + y = 80
x = 80 - y
x = 4y + 5 ... (3)
putting value of x in equation 3
80 - y = 4y + 5
5y = 75
y = 15
x = 80 - 15 = 65
Thus, larger number is 65 and smaller number is 15.
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