The sum of two numbers is 80 the greater number is ecreeds twice the smaller number by 11. Find the numbers.
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Let the greater number be x and the smaller be y
According to question -
x + y = 80
x - 2y = 11
[These are the simultaneous linear equations we get]
Evaluation -
x + y = 80
x - 2y = 11
- + - [The signs will change because of - (minus sign) outside]
After solving we get...
3y = 69
=> y = 23
[With this we will find x...]
x + y = 80 (given)
=> x + 23 = 80
=> x = 80-23 = 57
Answer : x = 57 ; y = 23
The greater number is 57 and the smaller number is 23.
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