Question

the sum of two numbers is 80.ther difference is 16.what are the numbers?

Answer 1

let one no. be x
let other no. be 80-x
ATQ
x-(80-x) =16
x-80+x=16
2x=16+80=96
x= 96/2=48
One no.=x=48
other no. =80-x=80-48=32
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Answer 2

Let the smaller number be x. The bigger number is 80-x

Given difference of the numbers is 16.

(80-x)-x = 16

80-x-x = 16

80-2x = 16

2x = 80-16

2x = 64

x = 64/2

x = 32

Therefore, the smaller number is 32. The bigger number is 80-x => 80-32 => 48.

The two numbers are 32 and 48