The sum of two numbers is 84.The first is 9 morve than 4 times the second
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0
Answer:
Required numbers are 15 and 69.
Step-by-step explanation:
Let the required two numbers are x and y.
Given that the sum of both the numbers is 84.
So, x + y =84 ...( i )
According to the question : -
First number is 9 more than 4 times of the second number.
So, x = 9 + ( 4 times of y )
⇒ x = 9 + ( 4 x y )
⇒ x = 9 + 4y
Now, numbers are 9 + 4y and y.
Substitute the value of 9 + 4y in ( i )
⇒ 9 + 4y + y = 84
⇒ 9 + 5y = 84
⇒ 5y = 84 - 9
⇒ 5y = 75
⇒ y = 75 / 5
⇒ y = 15
Therefore,
Numbers are y = 15 and 9 + 4y ⇒ 9 + 4( 15 ) ⇒ 9 + 60 ⇒ 69.
Answered by
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here is your answer OK ☺☺☺☺☺☺
Let the first number = x
then second number = 4x
according to question,
x + 4x = 80⇒ 5x = 80 ⇒ x = 16
so, first number = 16
and second number = 16 × 4 = 64
Let the first number = x
then second number = 4x
according to question,
x + 4x = 80⇒ 5x = 80 ⇒ x = 16
so, first number = 16
and second number = 16 × 4 = 64
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