the sum of two numbers is 9 and the sum of their reciprocals is 1/2 find the numbers.
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Assumption,
First number = p
Second number = 9 - p
Situation,
1/p + 1/(9 - p) = 1/2
(9 - p) + p/p(9 - p) = 1/2
p(9 - p) = 18
p² - 9p + 18 = 0
Splitting the middle term,
p² - 6p - 3p + 18 = 0
p(p - 6) - 3(p - 6) = 0
(p - 6)(p - 3) = 0
p - 6 = 0 or p - 3 = 0
p = 6, 3
So,
First Number = 6, 3
Second Number = 3, 6
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