Question

The sum of two numbers is 9 and the sum of their square is 81.Taking one number as x and solve it to find the number​

Answer 1

given

sum of two numbers is 9

one no. is x

so the other number is 9-x

$x^{2} +(9-x)^{2} =81$

$x^{2} +9^{2} +x^{2} -2*9*x$ =81

$x^{2} + 81+x^{2} -18x=81$

$2x^{2} =18x$

$x=9$

therefore the numbers are 9 and 0

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