the sum of two numbers is 9 and the sum of there square is 41 . Taking one number as x , and solve it to find the number
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HERE IS THE SOLUTION FOR YOUR QUESTION;
£ Firstly, We will make two equations from the question then, we will find the numbers.
◆ According To The Question ◆
Let The second number be y.
So,
x+y=9.......Eq" 1.
£ Similarly the other equation;
![x {}^{2} + y {}^{2} = 41.....eq \: 2. \\ x {}^{2} + y {}^{2} = 41.....eq \: 2. \\](https://tex.z-dn.net/?f=x+%7B%7D%5E%7B2%7D+%2B+y+%7B%7D%5E%7B2%7D+%3D+41.....eq+%5C%3A+2.+%5C%5C+)
Now by using Substitution Method;
x=9-y. 【From 1】 ......Eq.3
【After this refer the Image.】
Note : In the last step I have put the value of y in eq"3. To get the value of x.
HOPE IT HELPS
£ Firstly, We will make two equations from the question then, we will find the numbers.
◆ According To The Question ◆
Let The second number be y.
So,
x+y=9.......Eq" 1.
£ Similarly the other equation;
Now by using Substitution Method;
x=9-y. 【From 1】 ......Eq.3
【After this refer the Image.】
Note : In the last step I have put the value of y in eq"3. To get the value of x.
HOPE IT HELPS
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DonDj:
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