Question

The sum of two numbers is 9 and three times one of them is less than four times the second by one find the largest number

Answer 1

Let those number be x , y
Since, the sum of two numbers is 9
x + y = 9
x = 9 - y (1)
And also, three times one of them is less than four times the second by one
3x + 1 = 4y
3x = 4y - 1 (2)
Now putting the value of x from (1) into (2)
3*( 9 - y ) = 4y - 1
27 - 3y = 4y - 1
28 = 7y
y = 4

Puttig this value of y in (1)
x = 9 - 4
x = 5
So, the largest number is 5

Answer 2

Step-by-step explanation:

5 is the largest number of this question