Question

The sum of two numbers is 90 and the greater number exceeds the three times of the smaller number by 14, find the smaller number.
21
13
19
12​

Answer 1

Answer:

smaller number is 19.

Step-by-step explanation:

let the greater number be 'a' and smaller digit be 'b'.

given,

a = 3b + 14. -> 1

a + b = 90

3b + 14 + b = 90 ( by 1)

4b + 14 = 90

4b = 90 - 14

b = 76/4

b = 19.