The sum of two numbers is 90 and the greater number exceeds thrice the smaller by 14. Find the numbers plz?
Answers
Answered by
157
Here is your answer :-
Sum of two numbers = 90
Let the smaller number be x.
Then, greater number = (90-x)
It is given that, greater number exceeds thrice the smaller by 14.
A/q,
➡ 3(x) + 14 = 90 - x
➡ 3x + x = 90 - 14
➡ 4x = 76
➡ x = 76/4
➡ x = 19.
Answer :-
➡ Smaller number = x = 19
➡ Greater number = (90-x) = (90-19) = 71.
Hope it will help you !!!
Sum of two numbers = 90
Let the smaller number be x.
Then, greater number = (90-x)
It is given that, greater number exceeds thrice the smaller by 14.
A/q,
➡ 3(x) + 14 = 90 - x
➡ 3x + x = 90 - 14
➡ 4x = 76
➡ x = 76/4
➡ x = 19.
Answer :-
➡ Smaller number = x = 19
➡ Greater number = (90-x) = (90-19) = 71.
Hope it will help you !!!
Anonymous:
if it helps u, mark as brainliest !!
Answered by
15
Hi ,
Let x , ( 90 - x ) two numbers ,
According to the problem given ,
Greater number exceeds thrice the
smaller by 14
x - 2( 90 - x ) = 14
x - 180 + 2x = 14
3x = 14 + 180
3x = 194
x = 194/3
x = 64.
Therefore ,
Required two numbers are
greater no =64 ,
Smaller number = 90 - x
= 90 - 64
= 24
I hope this helps ya
Let x , ( 90 - x ) two numbers ,
According to the problem given ,
Greater number exceeds thrice the
smaller by 14
x - 2( 90 - x ) = 14
x - 180 + 2x = 14
3x = 14 + 180
3x = 194
x = 194/3
x = 64.
Therefore ,
Required two numbers are
greater no =64 ,
Smaller number = 90 - x
= 90 - 64
= 24
I hope this helps ya
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