Question

The sum of two numbers is 95. If one exceeds the other by 15, then the smaller of the two is
a. 40
b. 35
c. 45
d. 55

Answer 1

Answer:

Sum of two no is 95.

Let the numbers be X and Y.

So X + Y = 95.

Step-by-step explanation:

One no exceeds another by 15.

Therefore Y = X +15.

X +Y = 95

X + (X +15) =95.

X +X + 15 = 95.

2X= 80.

X = 80/2 =40.

Y = X +15 = 40 +15 = 55.

Therefore smaller of the two is a).40

Answer 2

Answer :

[ Option a. 40 ] is the correct option.

Step-by-step explanation :

To Find,

• The smaller number

Solution,

Given that,

• The sum of two numbers is 95
• One exceeds the other by 15

Therefore,

Let us assume the number as x and the number that exceeds the other by 15 as x + 15

A . T . Q

» x + x + 15 = 95

» 2x + 15 = 95

» 2x = 95 - 15

» 2x = 80

» x = 80 / 2

» x = 40

Therefore, the value of x is 40.

And the numbers are :-

The number which we assumed as x

» x = 40

The number which we assumed as x + 15

» x + 15

» 40 + 15

» 55

The smaller number is 40, as 55 > 40

∴ Hence, the smaller number is 40