Question

the sum of two numbers is 95.if one number exceeds the other by 15 then the smaller number is​

Answer 1

Answer:

hey mate

Step-by-step explanation:

let the two no be x and y

x+y = 95 ----->1

let y be the no exceed the other by 15

y = x+15 put in eq 1

x +x+15 = 95

2x = 80

x = 40 y = x+15 = 40+15 = 55

so smallest is x which is 40

hope it help u

Answer 2

Answer:

let the larger no be x and the smaller be y.

according to the question

x+y=95-----------1

x=y+15-------------2

From one and two

(y+15)+y=95

y+15+y=95

2y=95-15

2y=80

y=80/2

y = 40

The smaller number is 40