Math, asked by arzoekaur, 3 months ago

The sum of two numbers is 97. The larger number is three less than four times the smaller number. Find the numbers.

Answers

Answered by TheMoonlìghtPhoenix
59

Step-by-step explanation:

Answer:-

Given that:-

  • Sum of two numbers is 97.
  • The larger number 3 times less than 4 times smaller number.

Concept:-

Step by step formation of the equation:-

  • So, let the number be \sf{x}
  • Larger number is \sf{4x-3}

Let's Do!

\sf{x+ 4x-3=97}

\sf{x+ 4x- 3=97}

\sf{5x=97+3}

\sf{5x= 100}

\sf{x= \dfrac{100}{5}}

\sf{x= 20}

So, \sf{x= 20} is the smaller number.

What about the larger one??

Simple, placement of x in the equation.

\sf{4x-3}

= \sf{4(20)-3} [Breaking down of Brackets]

= \sf{80-3 }

= \sf{77}

= \sf{77} is the second number.


MisterIncredible: Awesome work
Answered by Anonymous
159

Step-by-step explanation:

 \sf \underline{Given} :

  • The sum of two numbers is 97.

  • The larger number is three less than four times the smaller number.

 \sf \underline{To  \: Find} :

  • Find the numbers.

 \sf \underline{Solution \: } :

.

Let the number is x

Larger number is 4(x - 3)

 \underline{ \boldsymbol{According \: to \: the \: question\: }} :  \:

\sf \leadsto \: 4x - 3  + x = 97 \\  \\  \sf \:  \leadsto \: 5x = 97  + 3 \\  \\ \sf \leadsto \: 5x = 100 \\  \\ \sf \leadsto \: x =   \cancel{\frac{100}{5} } \\  \\ \sf \leadsto \:  x \:  = 20

Substitute the value of x :

 \sf \leadsto \:  large  \: number = 4(20)-3 \\  \\  \sf \: \leadsto \:  large  \: number  = 80 - 3 \\  \\ \sf \: \leadsto \:  large  \: number =  \underline{77}

 \sf \underline{Verification} :

 \sf \: 20+77= 97 \: proved


TheMoonlìghtPhoenix: Great!
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