Question

the sum of two numbers is equals to 80 and the greater number exceeds twice the smaller number by 11 find the number ​

Answer 1

Answer:

suppose x be the greater number

so

x= 2y

and

x+y = 80

substitute 2y in place of x

2y +y = 80

3y= 80

y= 80/3

y= 26.7

x= 2y

x= 2(26.7)

x= 53.4

Answer 2

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Let the number be x

Then greater number = 2x + 11

Sum of two numbers = 80

x + 2 + 11 = 80

3x = 80 - 11

3x = 69

x = 23

Hence, smaller number = 23

Greater number = 2 × 23 + 11 = 57