Question

The sum of two numbers is twelve and their difference is eight.

Answer 1

Answer:

a = 10 and b = 2

Step-by-step explanation:

Let the numbers be a and b.

a+b=12 (given) - 1

a-b=8  (given) - 2

add the 2 equations,

add 1 and 2,

a+b+(a-b) = 12+8

a+a+b-b = 20

2a = 20

a = $\frac{20}{2}$

  = 10

substituting value of a in eqn 1,

10+b=12

b=12-10

 = 2

Hope this Helped,

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