Math, asked by preethirajmohan06, 5 months ago

The sum of two numbers is468and their HCF is39 how many pairs of such number can be formed​

Answers

Answered by mathdude500
0
Required pair is of the form : 39x , 39y
39x + 39y = 468
x + y = 12
Poosible pairs

1,11 and u get 39,429
5,7 and u 195,273
We cant choose even numbers otherwise hcf changes
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