Question

the sum of two numbers of 567 then other number?​

Answer 1

Let two numbers be x and y.

Since LCM*HCF=xy ,we get xy=5103. We are given that x-y=18. Use (x+y)^2=(x-y)^2+4xy yo get (x+y). It comes out to be 144. Now solve (x+y)=144 and (x-y)=18 simultaneously to get x=81 and y=63.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

the numbers are

283 and 284

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