Question

The sum of two numbers, one of which
is three fourth of other is 7. Find the number.whats the equation for it​

Answer 1

$\underline{\underline{\blue{\bf Answer:- }}}$

$\therefore\tt First \:Number \\\tt \therefore Second\:Number = \dfrac{3}{16}$

$\underline{\underline{\orange{\bf Step\:by\: Step-by-step\: Explanation:- }}}$

$\underline{\red{\bf Given:- }}$

$\tt:\implies Sum\:of\: two\:numbers\:is\:7.$

$\tt:\implies One\:number\:is\:\frac{3}{4}\:of\: other.$

$\underline{\green{\bf To\:Find:- }}$

$\tt:\implies The \; two\;numbers.\\\tt:\implies The \:equ^{n}\;for\;it.$

$\tt Let\:us\:take:-$

• $\tt First\: Number\:be\:x.$
• $\tt Second\: Number\:be\:\dfrac{3}{4}x$

• According to Question :-

$\tt:\implies x + \dfrac{3}{4}x = 7 \\\\\tt:\implies \dfrac{4x + 3x }{4}=7\\\\\tt:\implies \dfrac{7x}{4}=7\\\\\tt:\implies x =\dfrac{7\times 7}{4}\\\\\tt\green{:\implies x = \dfrac{1}{4}}$

$\boxed{\pink{\tt\circ First \:number = x =\dfrac{1}{4} }}$

$\boxed{\pink{\tt\circ Second\: number = \dfrac{3}{4}x =\dfrac{3}{16} }}$