Question

The sum of two numbers the numbers is 9 . The difference
their squarer is also 9. Find the number.​

Answer 1

Answer:

Let the first number be a

Second number = 9 - a

According to question,

a^2 - ( 9-a)^2 = 9

=> a^2 - ( 81 + a^2 - 18a) = 9

=> a^2 - 81 - a^2 + 18a = 9

=> 18a = 90

=> a = 5

First number = 5

Second number = 4