The sum of two numders is 1000 and the difference between their square is 25600, then the numbers are. A) 616 and 384 B) 628 and 372 C) 564 and 436 D) none
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Let the numbers are x and y
According to the question
⇒x+y=1000.....eq1
⇒x² – y² = 256000
⇒x² – y² =(x+y)(x−y)
⇒1000∗(x−y)=256000
⇒x−y=256.....eq2
Adding eq1 and eq2
⇒2x=1256⇒x=628
Put the value of x in eq1
⇒628+y=1000⇒y=372
The numbers are 628 and 372
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