The sum of two nymbers is 16 and the sum of their inverses is 1/3 find the number
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x+y=16
(1/x)+(1/y)=(1/3)
(y+x)/xy=(1/3)
16/xy= 1/3
XY= 16×3
XY = 48
x(16-y)= 48
16x -xy= 48
16x-48= 48
16x= 48+48
16x=96
x= 96/16
x=6
y=(16-x)
y=16-6
y=10
(1/x)+(1/y)=(1/3)
(y+x)/xy=(1/3)
16/xy= 1/3
XY= 16×3
XY = 48
x(16-y)= 48
16x -xy= 48
16x-48= 48
16x= 48+48
16x=96
x= 96/16
x=6
y=(16-x)
y=16-6
y=10
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