the sum of two opposite angle of a parallelogram is130 degree .find the mesare of each of angle
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Answer:
ABCD is a parallelogram.
∠B+∠D=130
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∠B=∠D (opposite angles of a parallelogram are equal)
∠B=∠B=130
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2∠B=130
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∠B=
2
130
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∠B=65
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Now ∠B+∠C=180
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(adjacent angles of a parallelogram are supplementary )
∠C=180
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−∠B=180
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−65
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∠C=115
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∴∠A=∠C=115
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(opp. angles of parallelogram are equal)
∴∠B=∠D=65
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and ∠A=∠C=115
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