Question

The sum of two opposite angles of a parallelogram are (5x-2)°and (40-x)°.find the value of x

Answer 1

SOLUTION....

We know that the opposite angles of a parallelogram are equal.
So,
5x-2=40-x
5x+x = 40+2
6x = 42
x = 42÷6
x = 7°

☆☆☆☆ HOPE THIS WILL HELP YOU....

Answer 2

$<b><u><i>$As we know, just like the opposite sides, the opposite angles of parallelogram are always equal.

So,

$= > (5x - 2) = (40 - x) \\ \\ = > 5x - 2 = 40 - x \\ \\ = > 5x + x - 2 = 40 \\ \\ = > 6x - 2 = 40 \\ \\ = > 6x = 40 + 2 \\ \\ = > 6x = 42 \\ \\ = > x = \frac{42}{6} \\ \\ = > x = 7$

If, x = 7

Then, measure of 1st angle :

=> ( 5x - 2 )°
=> ( 5 × 7 - 2 )°
=> ( 35 - 2 )°
=> 33°

And, measure of 2nd angle :

=> ( 40 - x )°
=> ( 40 - 7 )°
=> 33°