The sum of two opposite angles of a parallelogram is 130° . find the angles of the parallelogram
picachoo:
angle A = c and b = d because parallelogram's opposite sides are equal. let the b and d = x° ' so- 2x =130°=65°.then. angle a and c = 65°and angle b and d =y°.angle(a+b+c+d) = 360° and 65+y+65+y=360 then 2y +130=360 .2y=230 then.y= 115°
am i right
Answers
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Heya friend,
Given that
Sum of two opposite angles of parallelogram = 130°.
Solution
Let ABCD is a parallelogram and <A + <C = 130°.
We know that opposite angles of parallelogram are equal.
Let <A and <C be x. Then,
<A+<C = 130°
x + x = 130°
2x = 130°
x = 130°/2
x = 65°
Hence, <A and <C is equal to 65°.
<A + <B = 180° {co - interior}
65° + <B = 180°
<B = 180°-65°
<B = 115°
Hence, <B = <D = 115° {opposite angles of parallelogram are equal}.
So,
<A = 65°
<B = 115°
<C = 65°
<D = 115°.
Thanks
Hope it helps you.
With regards@
Tanisha
Given that
Sum of two opposite angles of parallelogram = 130°.
Solution
Let ABCD is a parallelogram and <A + <C = 130°.
We know that opposite angles of parallelogram are equal.
Let <A and <C be x. Then,
<A+<C = 130°
x + x = 130°
2x = 130°
x = 130°/2
x = 65°
Hence, <A and <C is equal to 65°.
<A + <B = 180° {co - interior}
65° + <B = 180°
<B = 180°-65°
<B = 115°
Hence, <B = <D = 115° {opposite angles of parallelogram are equal}.
So,
<A = 65°
<B = 115°
<C = 65°
<D = 115°.
Thanks
Hope it helps you.
With regards@
Tanisha
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