the sum of two opposite angles of a parallelogram is 140 degree . find all the angles ofa parallelogram?
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Answered by
124
since opp. angles of a parallelogram is equal.
therefore,
let the angle be x
thus,
x+x=140
2x=140
x=70°
co interior angles are supplimentary,
thus,
x+y=180
y=180-70
y=110°
opp. angles are equal thus,
fourth angle =110°
1st angle=70
2nd angle=70
3rd angle =110°
therefore,
let the angle be x
thus,
x+x=140
2x=140
x=70°
co interior angles are supplimentary,
thus,
x+y=180
y=180-70
y=110°
opp. angles are equal thus,
fourth angle =110°
1st angle=70
2nd angle=70
3rd angle =110°
sharmagirl1:
what isyahan
Answered by
90
we know that opposite angles of a ||gm are equal
therefore, 140°÷2=70° each
let angleA+angleB+angleC+angleD=360° (angle sum property of a ∆)
70°+70°+x+x=360
=>140°+2x=360
=>2x=360-140
=>2x=220
=>x=220÷2
=>x=110°
Hence all the angles of the ||gm are 70°, 70°, 110° and 110°.
May this help you buddy...
Plz mark as brainliest if it's helpful and correct...
therefore, 140°÷2=70° each
let angleA+angleB+angleC+angleD=360° (angle sum property of a ∆)
70°+70°+x+x=360
=>140°+2x=360
=>2x=360-140
=>2x=220
=>x=220÷2
=>x=110°
Hence all the angles of the ||gm are 70°, 70°, 110° and 110°.
May this help you buddy...
Plz mark as brainliest if it's helpful and correct...
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