The sum of two opposite angles of a parallelogram is 300°. find the measure of other two angles.
Answers
Answered by
9
hey mate this is your answers
we know that opposite angles of parallelogram are equal
let angle D of parallelogram be x
other angle B = x
and according to question ,
angle A + angle C = 150°
=> sum of all angles of quadrilaterals is 360°
angle A + angle C+ angle B + angle D = 360°
=> 150°+x+x = 360°
=> 2x = 360-150 => 210°
x = 210/2 = 105°
hope this helps
we know that opposite angles of parallelogram are equal
let angle D of parallelogram be x
other angle B = x
and according to question ,
angle A + angle C = 150°
=> sum of all angles of quadrilaterals is 360°
angle A + angle C+ angle B + angle D = 360°
=> 150°+x+x = 360°
=> 2x = 360-150 => 210°
x = 210/2 = 105°
hope this helps
pavanmeena16200366:
this question is wrong because sum o f opposite angle of paralel gram is always 180
Answered by
25
heya!!!
sum of angles of a quadrilateral=360°
a+b+c+d =360°
a+c=300
b+d=60°
b=d(opposite angles of a quadrilateral are equal
b=d=30°
hope it helps you ☺️☺️
sum of angles of a quadrilateral=360°
a+b+c+d =360°
a+c=300
b+d=60°
b=d(opposite angles of a quadrilateral are equal
b=d=30°
hope it helps you ☺️☺️
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