the sum of two opposite angles of parallelogram is 130° find the angle of parallelogram
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In || gm ABCD, ∠A and ∠C are opposite angles.
∴ ∠A +∠C = 130°
But ∠A = ∠C (opposite angles)
∴ ∠A = ∠C = 130°/2 = 65°
But ∠A + ∠B = 180° (Sum of adjacent angles)
⇒ 65° + ∠B = 180°
⇒ ∠B = 180° - 65° = 115°
But ∠D = ∠B (opposite angles)
∴ ∠D = 115°
Hence, ∠A = 65°, ∠B = 115°, ∠C = 65°, ∠D = 115°
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