Math, asked by kendralustbest, 4 months ago

the sum of two positive integer is 34 and their difference is 8. find the product?

Answers

Answered by uniyalshreya111
0

Answer 273

Step-by-step explanation:

Let the two positive integers be x and y

Sum of 2 positive integers is 34

x+y=34x+y=34 ---- 1

Their difference is 8

x-y=8x−y=8 ---2

Add 1 and 2

x+y+x-y=34+8x+y+x−y=34+8

2x=422x=42

x=\frac{42}{2}x=

2

42

x=21x=21

Substitute the value in 1

21+y=3421+y=34

y=13y=13

So, Two integers are 21 and 13

Product of these integers =21 \times 13 =27321×13=273

Hence their product is 273

Answered by Anonymous
12

 \huge \color{cyan} \boxed{ \colorbox{black}{Answer}}

Let integers to be xny

 \green{x + y = 34..(1)}

 \pink{x - y=8..(2)}

From EQ 1 and 2

We get,

 \purple{x=13}

Now put the value of x in eq1

We get,

13ty 34

 \red{y-21}

Now the product is ,

 \blue{x * y = 13 * 12}

273 is the answer

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