the sum of two positive integer is 34 and their difference is 8. find the product?
Answers
Answered by
0
Answer 273
Step-by-step explanation:
Let the two positive integers be x and y
Sum of 2 positive integers is 34
x+y=34x+y=34 ---- 1
Their difference is 8
x-y=8x−y=8 ---2
Add 1 and 2
x+y+x-y=34+8x+y+x−y=34+8
2x=422x=42
x=\frac{42}{2}x=
2
42
x=21x=21
Substitute the value in 1
21+y=3421+y=34
y=13y=13
So, Two integers are 21 and 13
Product of these integers =21 \times 13 =27321×13=273
Hence their product is 273
Answered by
12
Let integers to be xny
From EQ 1 and 2
We get,
Now put the value of x in eq1
We get,
13ty 34
Now the product is ,
273 is the answer
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